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Mathematics > Number Theory

arXiv:2406.10404 (math)
[Submitted on 14 Jun 2024 ]

Title: Solvability of $\binom{2k}{k} = \binom{2a}{a} \binom{x+2b}{b}$

Title: $\binom{2k}{k} = \binom{2a}{a} \binom{x+2b}{b}$的可解性

Authors:Meaghan Allen
Abstract: Suppose $k,x,$ and $b$ are positive integers, and $a$ is a nonnegative integer such that $k=a+b$. In this paper, we will prove $\binom{2k}{k} = \binom{2a}{a} \binom{x+2b}{b}$ if and only if $x=a=1$. We do this by looking at different cases depending on the values of $x$ and $k$. We use varying techniques to prove the cases, such as direct proof, verification through Maple software, and a proof technique found in Moser's paper. Previous results from Hanson, St\u{a}nic\u{a}, Shanta, Shorey and Nair are also used.
Abstract: 假设$k,x,$和$b$是正整数,$a$是一个非负整数,使得$k=a+b$。在本文中,我们将证明$\binom{2k}{k} = \binom{2a}{a} \binom{x+2b}{b}$当且仅当$x=a=1$。 我们通过根据$x$和$k$的不同取值来分析不同的情况。 我们使用不同的技巧来证明这些情况,例如直接证明、通过 Maple 软件进行验证,以及在 Moser 的论文中找到的证明技巧。 还使用了 Hanson、Stănică、Shanta、Shorey 和 Nair 的先前结果。
Subjects: Number Theory (math.NT)
MSC classes: 11B65 (Primary) 05A10 (Secondary)
Cite as: arXiv:2406.10404 [math.NT]
  (or arXiv:2406.10404v1 [math.NT] for this version)
  https://doi.org/10.48550/arXiv.2406.10404
arXiv-issued DOI via DataCite

Submission history

From: Meaghan Allen [view email]
[v1] Fri, 14 Jun 2024 20:14:17 UTC (6 KB)
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