标题： $π(x)$和$π((x+1)^{2})-π(x^{2})$的边界估计 显示英文标题

标题： Estimates of the bounds of $π(x)$ and $π((x+1)^{2})-π(x^{2})$

摘要： 我们使用解析数论中的原理，展示了素数计数函数$\pi(x)$的以下界限，给出一个估计：$$2 \log 2 \geq \limsup_{x \rightarrow \infty} \frac{\pi(x)}{x / \log x} \geq \liminf_{x \rightarrow \infty} \frac{\pi(x)}{x / \log x} \geq \log 2$$对所有足够大的$x$成立。 我们还对$\pi((x+1)^{2}) - \pi(x^{2})$的界限进行了猜想，这与关于上述区间中素数数量的Legendre猜想相关，使得：$$ \left \lfloor\frac{1}{2}\left(\frac{\left(x+1\right)^{2}}{\log\left(x+1\right)}-\frac{x^{2}}{\log x}\right)-\frac{\left(\log x\right)^{2}}{\log\left(\log x\right)}\right \rfloor \leq \pi((x+1)^{2}) - \pi(x^{2}) \leq $$ $$ \left \lfloor\frac{1}{2}\left(\frac{\left(x+1\right)^{2}}{\log\left(x+1\right)}-\frac{x^{2}}{\log x}\right) + \log^{2}x\log\log x \right \rfloor$$ 显示英文摘要

摘要： We show the following bounds on the prime counting function $\pi(x)$ using principles from analytic number theory, giving an estimate: $$2 \log 2 \geq \limsup_{x \rightarrow \infty} \frac{\pi(x)}{x / \log x} \geq \liminf_{x \rightarrow \infty} \frac{\pi(x)}{x / \log x} \geq \log 2$$ for all $x$ sufficiently large. We also conjecture about the bounding of $\pi((x+1)^{2}) - \pi(x^{2})$, as is relevant to Legendre's conjecture about the number of primes in the aforementioned interval such that: $$ \left \lfloor\frac{1}{2}\left(\frac{\left(x+1\right)^{2}}{\log\left(x+1\right)}-\frac{x^{2}}{\log x}\right)-\frac{\left(\log x\right)^{2}}{\log\left(\log x\right)}\right \rfloor \leq \pi((x+1)^{2}) - \pi(x^{2}) \leq $$ $$ \left \lfloor\frac{1}{2}\left(\frac{\left(x+1\right)^{2}}{\log\left(x+1\right)}-\frac{x^{2}}{\log x}\right) + \log^{2}x\log\log x \right \rfloor$$